1130021311 has 2 divisors, whose sum is σ = 1130021312. Its totient is φ = 1130021310.

The previous prime is 1130021281. The next prime is 1130021351. The reversal of 1130021311 is 1131200311.

It is a weak prime.

It is an emirp because it is prime and its reverse (1131200311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1130021311 - 2¹⁵ = 1129988543 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1130021291 and 1130021300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130021351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565010655 + 565010656.

It is an arithmetic number, because the mean of its divisors is an integer number (565010656).

Almost surely, 2^1130021311 is an apocalyptic number.

1130021311 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130021311 is an equidigital number, since it uses as much as digits as its factorization.

1130021311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1130021311 is about 33615.7896084563. The cubic root of 1130021311 is about 1041.5869850886.

Adding to 1130021311 its reverse (1131200311), we get a palindrome (2261221622).

The spelling of 1130021311 in words is "one billion, one hundred thirty million, twenty-one thousand, three hundred eleven".