Base | Representation |
---|---|
bin | 1010010001110000101100… |
… | …1011011110000110110111 |
3 | 1111000021220121102211000122 |
4 | 2210130023023132012313 |
5 | 2440120401101341210 |
6 | 40011132300202155 |
7 | 2244262433343014 |
oct | 244341313360667 |
9 | 44007817384018 |
10 | 11300246512055 |
11 | 3667453617386 |
12 | 132609183935b |
13 | 63c7bb343887 |
14 | 2b0d1332670b |
15 | 148e2a80db55 |
hex | a470b2de1b7 |
11300246512055 has 8 divisors (see below), whose sum is σ = 13691949172512. Its totient is φ = 8952428304288.
The previous prime is 11300246512039. The next prime is 11300246512063. The reversal of 11300246512055 is 55021564200311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11300246512055 - 24 = 11300246512039 is a prime.
It is a super-2 number, since 2×113002465120552 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10971112604 + ... + 10971113633.
It is an arithmetic number, because the mean of its divisors is an integer number (1711493646564).
Almost surely, 211300246512055 is an apocalyptic number.
11300246512055 is a deficient number, since it is larger than the sum of its proper divisors (2391702660457).
11300246512055 is a wasteful number, since it uses less digits than its factorization.
11300246512055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21942226345.
The product of its (nonzero) digits is 36000, while the sum is 35.
The spelling of 11300246512055 in words is "eleven trillion, three hundred billion, two hundred forty-six million, five hundred twelve thousand, fifty-five".
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