Base | Representation |
---|---|
bin | 100001101011010… |
… | …1110100100111101 |
3 | 2220202100112200121 |
4 | 1003112232210331 |
5 | 4303242001141 |
6 | 304044254541 |
7 | 40001052151 |
oct | 10326564475 |
9 | 2822315617 |
10 | 1130031421 |
11 | 52a967372 |
12 | 276541451 |
13 | 15016705c |
14 | aa119061 |
15 | 693191d1 |
hex | 435ae93d |
1130031421 has 4 divisors (see below), whose sum is σ = 1130371200. Its totient is φ = 1129691644.
The previous prime is 1130031379. The next prime is 1130031431. The reversal of 1130031421 is 1241300311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1241300311 = 29 ⋅42803459.
It is a cyclic number.
It is not a de Polignac number, because 1130031421 - 229 = 593160509 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1130031395 and 1130031404.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1130031431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164851 + ... + 171568.
It is an arithmetic number, because the mean of its divisors is an integer number (282592800).
Almost surely, 21130031421 is an apocalyptic number.
It is an amenable number.
1130031421 is a deficient number, since it is larger than the sum of its proper divisors (339779).
1130031421 is an equidigital number, since it uses as much as digits as its factorization.
1130031421 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 339778.
The product of its (nonzero) digits is 72, while the sum is 16.
The square root of 1130031421 is about 33615.9399838826. The cubic root of 1130031421 is about 1041.5900913466.
Adding to 1130031421 its reverse (1241300311), we get a palindrome (2371331732).
The spelling of 1130031421 in words is "one billion, one hundred thirty million, thirty-one thousand, four hundred twenty-one".
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