11300413140 has 192 divisors, whose sum is σ = 35774323200. Its totient is φ = 2960851968.

The previous prime is 11300413139. The next prime is 11300413169. The reversal of 11300413140 is 4131400311.

11300413140 is a `hidden beast` number, since 11 + 300 + 41 + 314 + 0 = 666.

11300413140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 17305054 + ... + 17305706.

It is an arithmetic number, because the mean of its divisors is an integer number (186324600).

Almost surely, 2^11300413140 is an apocalyptic number.

11300413140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11300413140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17887161600).

11300413140 is an abundant number, since it is smaller than the sum of its proper divisors (24473910060).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11300413140 is a wasteful number, since it uses less digits than its factorization.

11300413140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1183 (or 1175 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 11300413140 its reverse (4131400311), we get a palindrome (15431813451).

The spelling of 11300413140 in words is "eleven billion, three hundred million, four hundred thirteen thousand, one hundred forty".