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113005115 = 522601023
BaseRepresentation
bin1101011110001…
…01001000111011
321212122020212122
412233011020323
5212412130430
615114031455
72541345656
oct657051073
9255566778
10113005115
1158874463
1231a1858b
131a548142
141101889d
159dc2ee5
hex6bc523b

113005115 has 4 divisors (see below), whose sum is σ = 135606144. Its totient is φ = 90404088.

The previous prime is 113005033. The next prime is 113005117. The reversal of 113005115 is 511500311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113005115 - 214 = 112988731 is a prime.

It is a Duffinian number.

It is a plaindrome in base 9.

It is a junction number, because it is equal to n+sod(n) for n = 113005093 and 113005102.

It is not an unprimeable number, because it can be changed into a prime (113005117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11300507 + ... + 11300516.

It is an arithmetic number, because the mean of its divisors is an integer number (33901536).

Almost surely, 2113005115 is an apocalyptic number.

113005115 is a deficient number, since it is larger than the sum of its proper divisors (22601029).

113005115 is an equidigital number, since it uses as much as digits as its factorization.

113005115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22601028.

The product of its (nonzero) digits is 75, while the sum is 17.

The square root of 113005115 is about 10630.3863993742. The cubic root of 113005115 is about 483.4661072673.

Adding to 113005115 its reverse (511500311), we get a palindrome (624505426).

The spelling of 113005115 in words is "one hundred thirteen million, five thousand, one hundred fifteen".

Divisors: 1 5 22601023 113005115