Base | Representation |
---|---|
bin | 110100101000000011… |
… | …1001100001111001111 |
3 | 101210201002022000022122 |
4 | 1221100013030033033 |
5 | 3322422340241421 |
6 | 123530105203155 |
7 | 11110400311262 |
oct | 1512007141717 |
9 | 353632260278 |
10 | 113013212111 |
11 | 43a24014a58 |
12 | 19a9ba904bb |
13 | a870859057 |
14 | 5681468cd9 |
15 | 2e168eb2ab |
hex | 1a501cc3cf |
113013212111 has 2 divisors, whose sum is σ = 113013212112. Its totient is φ = 113013212110.
The previous prime is 113013212071. The next prime is 113013212113. The reversal of 113013212111 is 111212310311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113013212111 is a prime.
It is a super-2 number, since 2×1130132121112 (a number of 23 digits) contains 22 as substring.
Together with 113013212113, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 113013212111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113013212113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56506606055 + 56506606056.
It is an arithmetic number, because the mean of its divisors is an integer number (56506606056).
Almost surely, 2113013212111 is an apocalyptic number.
113013212111 is a deficient number, since it is larger than the sum of its proper divisors (1).
113013212111 is an equidigital number, since it uses as much as digits as its factorization.
113013212111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36, while the sum is 17.
Adding to 113013212111 its reverse (111212310311), we get a palindrome (224225522422).
The spelling of 113013212111 in words is "one hundred thirteen billion, thirteen million, two hundred twelve thousand, one hundred eleven".
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