Base | Representation |
---|---|
bin | 10000011100100101110… |
… | …001000000010010110111 |
3 | 11000001021021111212211112 |
4 | 100130211301000102313 |
5 | 122004132230031403 |
6 | 2223113350425235 |
7 | 144440441336300 |
oct | 20344561002267 |
9 | 4001237455745 |
10 | 1130210002103 |
11 | 3a6357099786 |
12 | 16306106221b |
13 | 8276981a170 |
14 | 3c9b97797a7 |
15 | 1e5ecc5c9d8 |
hex | 10725c404b7 |
1130210002103 has 24 divisors (see below), whose sum is σ = 1415980214208. Its totient is φ = 894160886976.
The previous prime is 1130210002093. The next prime is 1130210002111. The reversal of 1130210002103 is 3012000120311.
It is not a de Polignac number, because 1130210002103 - 210 = 1130210001079 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1130210001103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8811650 + ... + 8938992.
It is an arithmetic number, because the mean of its divisors is an integer number (58999175592).
Almost surely, 21130210002103 is an apocalyptic number.
1130210002103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1130210002103 is a deficient number, since it is larger than the sum of its proper divisors (285770212105).
1130210002103 is a wasteful number, since it uses less digits than its factorization.
1130210002103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 141303 (or 141296 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 1130210002103 its reverse (3012000120311), we get a palindrome (4142210122414).
The spelling of 1130210002103 in words is "one trillion, one hundred thirty billion, two hundred ten million, two thousand, one hundred three".
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