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1130220123120 = 2433511736131063
BaseRepresentation
bin10000011100100110010…
…111100111001111110000
311000001021222120002021000
4100130212113213033300
5122004142322414440
62223114351402000
7144440623351524
oct20344627471760
94001258502230
101130220123120
113a6361881860
12163064523300
138276b951b2a
143c9bac51d84
151e5edaab730
hex107265e73f0

1130220123120 has 640 divisors, whose sum is σ = 4316143749120. Its totient is φ = 269544775680.

The previous prime is 1130220123083. The next prime is 1130220123167. The reversal of 1130220123120 is 213210220311.

1130220123120 is a `hidden beast` number, since 1 + 130 + 220 + 1 + 2 + 312 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 1130220123093 and 1130220123102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1063235709 + ... + 1063236771.

It is an arithmetic number, because the mean of its divisors is an integer number (6743974608).

Almost surely, 21130220123120 is an apocalyptic number.

1130220123120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1130220123120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2158071874560).

1130220123120 is an abundant number, since it is smaller than the sum of its proper divisors (3185923626000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1130220123120 is a wasteful number, since it uses less digits than its factorization.

1130220123120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1782 (or 1770 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 1130220123120 its reverse (213210220311), we get a palindrome (1343430343431).

The spelling of 1130220123120 in words is "one trillion, one hundred thirty billion, two hundred twenty million, one hundred twenty-three thousand, one hundred twenty".