Base | Representation |
---|---|
bin | 1010010001111000000110… |
… | …0001100000101100110101 |
3 | 1111000111000222111010021120 |
4 | 2210132001201200230311 |
5 | 2440133432343020313 |
6 | 40012101304134153 |
7 | 2244362562620340 |
oct | 244360141405465 |
9 | 44014028433246 |
10 | 11302232001333 |
11 | 3668282352909 |
12 | 1326546767359 |
13 | 63ca467aa1c0 |
14 | 2b1060cc5457 |
15 | 148ee4ca6d23 |
hex | a4781860b35 |
11302232001333 has 64 divisors (see below), whose sum is σ = 20315449244160. Its totient is φ = 5417453002752.
The previous prime is 11302232001331. The next prime is 11302232001337. The reversal of 11302232001333 is 33310023220311.
It is not a de Polignac number, because 11302232001333 - 21 = 11302232001331 is a prime.
It is a super-3 number, since 3×113022320013333 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11302232001331) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 41853360 + ... + 42122537.
It is an arithmetic number, because the mean of its divisors is an integer number (317428894440).
Almost surely, 211302232001333 is an apocalyptic number.
11302232001333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11302232001333 is a deficient number, since it is larger than the sum of its proper divisors (9013217242827).
11302232001333 is a wasteful number, since it uses less digits than its factorization.
11302232001333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83975966.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 11302232001333 its reverse (33310023220311), we get a palindrome (44612255221644).
The spelling of 11302232001333 in words is "eleven trillion, three hundred two billion, two hundred thirty-two million, one thousand, three hundred thirty-three".
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