11303040122132 has 24 divisors (see below), whose sum is σ = 21579412774752. Its totient is φ = 5137535597600.

The previous prime is 11303040122117. The next prime is 11303040122147. The reversal of 11303040122132 is 23122104030311.

11303040122132 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11303040122117) and next prime (11303040122147).

It is a junction number, because it is equal to n+sod(n) for n = 11303040122098 and 11303040122107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4156094 + ... + 6314997.

It is an arithmetic number, because the mean of its divisors is an integer number (899142198948).

Almost surely, 2^{11303040122132} is an apocalyptic number.

It is an amenable number.

11303040122132 is a deficient number, since it is larger than the sum of its proper divisors (10276372652620).

11303040122132 is a wasteful number, since it uses less digits than its factorization.

11303040122132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10495639 (or 10495637 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 11303040122132 its reverse (23122104030311), we get a palindrome (34425144152443).

The spelling of 11303040122132 in words is "eleven trillion, three hundred three billion, forty million, one hundred twenty-two thousand, one hundred thirty-two".