Base | Representation |
---|---|
bin | 10000011100101011110… |
… | …110100110001010100000 |
3 | 11000001112101200120122212 |
4 | 100130223312212022200 |
5 | 122004334401144412 |
6 | 2223131435421252 |
7 | 144443121406664 |
oct | 20345366461240 |
9 | 4001471616585 |
10 | 1130312131232 |
11 | 3a63a9804919 |
12 | 16308b2b4828 |
13 | 82784a27abb |
14 | 3c9c91628a4 |
15 | 1e606bd3222 |
hex | 1072bda62a0 |
1130312131232 has 48 divisors (see below), whose sum is σ = 2356469177832. Its totient is φ = 531851304960.
The previous prime is 1130312131217. The next prime is 1130312131241. The reversal of 1130312131232 is 2321312130311.
It can be written as a sum of positive squares in 4 ways, for example, as 1092351064336 + 37961066896 = 1045156^2 + 194836^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1130312131198 and 1130312131207.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4881308 + ... + 5107620.
Almost surely, 21130312131232 is an apocalyptic number.
It is an amenable number.
1130312131232 is an abundant number, since it is smaller than the sum of its proper divisors (1226157046600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1130312131232 is a wasteful number, since it uses less digits than its factorization.
1130312131232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 235521 (or 235513 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1130312131232 its reverse (2321312130311), we get a palindrome (3451624261543).
The spelling of 1130312131232 in words is "one trillion, one hundred thirty billion, three hundred twelve million, one hundred thirty-one thousand, two hundred thirty-two".
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