Base | Representation |
---|---|
bin | 110100101000100111… |
… | …0111010010100101100 |
3 | 101210202101200012102120 |
4 | 1221101032322110230 |
5 | 3322442143404400 |
6 | 123532020152540 |
7 | 11111016154536 |
oct | 1512116722454 |
9 | 353671605376 |
10 | 113032013100 |
11 | 43a33696466 |
12 | 19aa6238750 |
13 | a87470c7b6 |
14 | 5683b60856 |
15 | 2e183b1ca0 |
hex | 1a513ba52c |
113032013100 has 36 divisors (see below), whose sum is σ = 327039292104. Its totient is φ = 30141870080.
The previous prime is 113032013063. The next prime is 113032013111. The reversal of 113032013100 is 1310230311.
It is a super-2 number, since 2×1130320131002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 113032013100.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 188386389 + ... + 188386988.
Almost surely, 2113032013100 is an apocalyptic number.
113032013100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113032013100 is an abundant number, since it is smaller than the sum of its proper divisors (214007279004).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113032013100 is a wasteful number, since it uses less digits than its factorization.
113032013100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 376773394 (or 376773387 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 113032013100 its reverse (1310230311), we get a palindrome (114342243411).
The spelling of 113032013100 in words is "one hundred thirteen billion, thirty-two million, thirteen thousand, one hundred".
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