Base | Representation |
---|---|
bin | 10101000011100101… |
… | …01100000100000111 |
3 | 1002011211010200111211 |
4 | 22201302230010013 |
5 | 141122403312210 |
6 | 5105415312251 |
7 | 550063265311 |
oct | 124162540407 |
9 | 32154120454 |
10 | 11304354055 |
11 | 4881016575 |
12 | 223597b687 |
13 | 10b1cbb1c7 |
14 | 7934987b1 |
15 | 46265d38a |
hex | 2a1cac107 |
11304354055 has 4 divisors (see below), whose sum is σ = 13565224872. Its totient is φ = 9043483240.
The previous prime is 11304354041. The next prime is 11304354059. The reversal of 11304354055 is 55045340311.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 55045340311 = 13 ⋅4234256947.
It is not a de Polignac number, because 11304354055 - 225 = 11270799623 is a prime.
It is a super-3 number, since 3×113043540553 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11304354059) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1130435401 + ... + 1130435410.
It is an arithmetic number, because the mean of its divisors is an integer number (3391306218).
Almost surely, 211304354055 is an apocalyptic number.
11304354055 is a deficient number, since it is larger than the sum of its proper divisors (2260870817).
11304354055 is an equidigital number, since it uses as much as digits as its factorization.
11304354055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2260870816.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 11304354055 its reverse (55045340311), we get a palindrome (66349694366).
The spelling of 11304354055 in words is "eleven billion, three hundred four million, three hundred fifty-four thousand, fifty-five".
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