11304403351 has 4 divisors (see below), whose sum is σ = 11969368272. Its totient is φ = 10639438432.

The previous prime is 11304403291. The next prime is 11304403361. The reversal of 11304403351 is 15330440311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15330440311 = 13259 ⋅1156229.

It is a cyclic number.

It is not a de Polignac number, because 11304403351 - 2²⁷ = 11170185623 is a prime.

It is a super-3 number, since 3×11304403351³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11304403361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 332482435 + ... + 332482468.

It is an arithmetic number, because the mean of its divisors is an integer number (2992342068).

Almost surely, 2^11304403351 is an apocalyptic number.

11304403351 is a deficient number, since it is larger than the sum of its proper divisors (664964921).

11304403351 is an equidigital number, since it uses as much as digits as its factorization.

11304403351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 664964920.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 11304403351 its reverse (15330440311), we get a palindrome (26634843662).

The spelling of 11304403351 in words is "eleven billion, three hundred four million, four hundred three thousand, three hundred fifty-one".