113044310224133 has 4 divisors (see below), whose sum is σ = 113158381173888. Its totient is φ = 112930239274380.

The previous prime is 113044310224099. The next prime is 113044310224199. The reversal of 113044310224133 is 331422013440311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113044310224133 - 2⁸ = 113044310223877 is a prime.

It is a super-3 number, since 3×113044310224133³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113044310224133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113044310244133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57035473391 + ... + 57035475372.

It is an arithmetic number, because the mean of its divisors is an integer number (28289595293472).

Almost surely, 2^{113044310224133} is an apocalyptic number.

It is an amenable number.

113044310224133 is a deficient number, since it is larger than the sum of its proper divisors (114070949755).

113044310224133 is an equidigital number, since it uses as much as digits as its factorization.

113044310224133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114070949754.

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 113044310224133 its reverse (331422013440311), we get a palindrome (444466323664444).

The spelling of 113044310224133 in words is "one hundred thirteen trillion, forty-four billion, three hundred ten million, two hundred twenty-four thousand, one hundred thirty-three".