Base | Representation |
---|---|
bin | 10101000011101010… |
… | …10011001110100011 |
3 | 1002011212102110202002 |
4 | 22201311103032203 |
5 | 141123042220010 |
6 | 5105442114215 |
7 | 550102146443 |
oct | 124165231643 |
9 | 32155373662 |
10 | 11305038755 |
11 | 4881443a3a |
12 | 223604b96b |
13 | 10b219aa5a |
14 | 7935d6123 |
15 | 4627461a5 |
hex | 2a1d533a3 |
11305038755 has 4 divisors (see below), whose sum is σ = 13566046512. Its totient is φ = 9044031000.
The previous prime is 11305038749. The next prime is 11305038761. The reversal of 11305038755 is 55783050311.
It is a happy number.
11305038755 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (11305038749) and next prime (11305038761).
It is not a de Polignac number, because 11305038755 - 212 = 11305034659 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1130503871 + ... + 1130503880.
It is an arithmetic number, because the mean of its divisors is an integer number (3391511628).
Almost surely, 211305038755 is an apocalyptic number.
11305038755 is a deficient number, since it is larger than the sum of its proper divisors (2261007757).
11305038755 is an equidigital number, since it uses as much as digits as its factorization.
11305038755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2261007756.
The product of its (nonzero) digits is 63000, while the sum is 38.
The spelling of 11305038755 in words is "eleven billion, three hundred five million, thirty-eight thousand, seven hundred fifty-five".
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