Base | Representation |
---|---|
bin | 1010010010010101001010… |
… | …0000000101000010001110 |
3 | 1111001020011122111111121202 |
4 | 2210211102200011002032 |
5 | 2440300421424000220 |
6 | 40015431335225502 |
7 | 2245060106363066 |
oct | 244452240050216 |
9 | 44036148444552 |
10 | 11310033031310 |
11 | 3670615881122 |
12 | 1327b63218292 |
13 | 6406baa36a80 |
14 | 2b15a0d983a6 |
15 | 1492eea9d275 |
hex | a495280508e |
11310033031310 has 64 divisors (see below), whose sum is σ = 22252679152704. Its totient is φ = 4113884236800.
The previous prime is 11310033031301. The next prime is 11310033031337. The reversal of 11310033031310 is 1313033001311.
It is a super-2 number, since 2×113100330313102 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 90701 + ... + 4756920.
It is an arithmetic number, because the mean of its divisors is an integer number (347698111761).
Almost surely, 211310033031310 is an apocalyptic number.
11310033031310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11310033031310 is a deficient number, since it is larger than the sum of its proper divisors (10942646121394).
11310033031310 is a wasteful number, since it uses less digits than its factorization.
11310033031310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4847909.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 11310033031310 its reverse (1313033001311), we get a palindrome (12623066032621).
The spelling of 11310033031310 in words is "eleven trillion, three hundred ten billion, thirty-three million, thirty-one thousand, three hundred ten".
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