Base | Representation |
---|---|
bin | 1010010010010101011010… |
… | …0011010111010001100000 |
3 | 1111001020100101101201221020 |
4 | 2210211112203113101200 |
5 | 2440301041324020222 |
6 | 40015442204125440 |
7 | 2245061563203261 |
oct | 244452643272140 |
9 | 44036311351836 |
10 | 11310101001312 |
11 | 3670650185a83 |
12 | 1327b81b36880 |
13 | 6406cbb445c9 |
14 | 2b15aa00c968 |
15 | 149305a2765c |
hex | a49568d7460 |
11310101001312 has 48 divisors (see below), whose sum is σ = 29689802618112. Its totient is φ = 3769933668480.
The previous prime is 11310101001253. The next prime is 11310101001359. The reversal of 11310101001312 is 21310010101311.
It is a tau number, because it is divible by the number of its divisors (48).
It is a junction number, because it is equal to n+sod(n) for n = 11310101001291 and 11310101001300.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2120637 + ... + 5207427.
It is an arithmetic number, because the mean of its divisors is an integer number (618537554544).
Almost surely, 211310101001312 is an apocalyptic number.
11310101001312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11310101001312 is an abundant number, since it is smaller than the sum of its proper divisors (18379701616800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11310101001312 is a wasteful number, since it uses less digits than its factorization.
11310101001312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3124971 (or 3124963 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 11310101001312 its reverse (21310010101311), we get a palindrome (32620111102623).
Subtracting 11310101001312 from its reverse (21310010101311), we obtain a palindrome (9999909099999).
The spelling of 11310101001312 in words is "eleven trillion, three hundred ten billion, one hundred one million, one thousand, three hundred twelve".
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