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1131010141 is a prime number
BaseRepresentation
bin100001101101001…
…1101100001011101
32220211012021020111
41003122131201131
54304014311031
6304121250021
740012266442
oct10332354135
92824167214
101131010141
11530475728
12276933911
1315041a691
14aa2d19c9
156945e1b1
hex4369d85d

1131010141 has 2 divisors, whose sum is σ = 1131010142. Its totient is φ = 1131010140.

The previous prime is 1131010061. The next prime is 1131010147. The reversal of 1131010141 is 1410101311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 918696100 + 212314041 = 30310^2 + 14571^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131010141 - 29 = 1131009629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131010147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565505070 + 565505071.

It is an arithmetic number, because the mean of its divisors is an integer number (565505071).

Almost surely, 21131010141 is an apocalyptic number.

It is an amenable number.

1131010141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131010141 is an equidigital number, since it uses as much as digits as its factorization.

1131010141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

The square root of 1131010141 is about 33630.4942128420. The cubic root of 1131010141 is about 1041.8907115679.

Adding to 1131010141 its reverse (1410101311), we get a palindrome (2541111452).

The spelling of 1131010141 in words is "one billion, one hundred thirty-one million, ten thousand, one hundred forty-one".