113101101341 has 2 divisors, whose sum is σ = 113101101342. Its totient is φ = 113101101340.

The previous prime is 113101101307. The next prime is 113101101343. The reversal of 113101101341 is 143101101311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90474624100 + 22626477241 = 300790^2 + 150421^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113101101341 is a prime.

Together with 113101101343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113101101343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56550550670 + 56550550671.

It is an arithmetic number, because the mean of its divisors is an integer number (56550550671).

Almost surely, 2^113101101341 is an apocalyptic number.

It is an amenable number.

113101101341 is a deficient number, since it is larger than the sum of its proper divisors (1).

113101101341 is an equidigital number, since it uses as much as digits as its factorization.

113101101341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 113101101341 its reverse (143101101311), we get a palindrome (256202202652).

The spelling of 113101101341 in words is "one hundred thirteen billion, one hundred one million, one hundred one thousand, three hundred forty-one".