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1131011102151 = 32738803462659
BaseRepresentation
bin10000011101010101100…
…000111101010111000111
311000010100002220222111200
4100131111200331113013
5122012302320232101
62223325045033543
7144466336514040
oct20352540752707
94003302828450
101131011102151
113a6728311037
121632453b58b3
1382866796968
143ca53d0d8c7
151e648250986
hex1075583d5c7

1131011102151 has 24 divisors (see below), whose sum is σ = 1867118098560. Its totient is φ = 646274005776.

The previous prime is 1131011102129. The next prime is 1131011102159. The reversal of 1131011102151 is 1512011101311.

It is not a de Polignac number, because 1131011102151 - 210 = 1131011101127 is a prime.

It is a super-2 number, since 2×11310111021512 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131011102159) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2213260 + ... + 2675918.

It is an arithmetic number, because the mean of its divisors is an integer number (77796587440).

Almost surely, 21131011102151 is an apocalyptic number.

1131011102151 is a deficient number, since it is larger than the sum of its proper divisors (736106996409).

1131011102151 is a wasteful number, since it uses less digits than its factorization.

1131011102151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 501475 (or 501472 counting only the distinct ones).

The product of its (nonzero) digits is 30, while the sum is 18.

Adding to 1131011102151 its reverse (1512011101311), we get a palindrome (2643022203462).

The spelling of 1131011102151 in words is "one trillion, one hundred thirty-one billion, eleven million, one hundred two thousand, one hundred fifty-one".

Divisors: 1 3 7 9 21 63 38803 116409 271621 349227 462659 814863 1387977 2444589 3238613 4163931 9715839 29147517 17952557177 53857671531 125667900239 161573014593 377003700717 1131011102151