11310301134131 has 2 divisors, whose sum is σ = 11310301134132. Its totient is φ = 11310301134130.

The previous prime is 11310301134091. The next prime is 11310301134133. The reversal of 11310301134131 is 13143110301311.

It is a strong prime.

It is an emirp because it is prime and its reverse (13143110301311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11310301134131 - 2¹⁰ = 11310301133107 is a prime.

It is a super-2 number, since 2×11310301134131² (a number of 27 digits) contains 22 as substring.

Together with 11310301134133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11310301134097 and 11310301134106.

It is not a weakly prime, because it can be changed into another prime (11310301134133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655150567065 + 5655150567066.

It is an arithmetic number, because the mean of its divisors is an integer number (5655150567066).

Almost surely, 2^{11310301134131} is an apocalyptic number.

11310301134131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11310301134131 is an equidigital number, since it uses as much as digits as its factorization.

11310301134131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 11310301134131 its reverse (13143110301311), we get a palindrome (24453411435442).

The spelling of 11310301134131 in words is "eleven trillion, three hundred ten billion, three hundred one million, one hundred thirty-four thousand, one hundred thirty-one".