Base | Representation |
---|---|
bin | 110100101010101111… |
… | …0001101100111100011 |
3 | 101210221100111110210200 |
4 | 1221111132031213203 |
5 | 3323113400230110 |
6 | 123543040400243 |
7 | 11112541524615 |
oct | 1512536154743 |
9 | 353840443720 |
10 | 113103133155 |
11 | 43a6a851a71 |
12 | 19b06016083 |
13 | a88638107c |
14 | 568d394db5 |
15 | 2e1e75e6c0 |
hex | 1a5578d9e3 |
113103133155 has 48 divisors (see below), whose sum is σ = 200424560544. Its totient is φ = 58987399680.
The previous prime is 113103133153. The next prime is 113103133181. The reversal of 113103133155 is 551331301311.
It is a happy number.
113103133155 is a `hidden beast` number, since 1 + 1 + 31 + 0 + 313 + 315 + 5 = 666.
It is not a de Polignac number, because 113103133155 - 21 = 113103133153 is a prime.
It is not an unprimeable number, because it can be changed into a prime (113103133153) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 276145 + ... + 549965.
It is an arithmetic number, because the mean of its divisors is an integer number (4175511678).
Almost surely, 2113103133155 is an apocalyptic number.
113103133155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
113103133155 is a deficient number, since it is larger than the sum of its proper divisors (87321427389).
113103133155 is a wasteful number, since it uses less digits than its factorization.
113103133155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 274036 (or 274033 counting only the distinct ones).
The product of its (nonzero) digits is 2025, while the sum is 27.
Adding to 113103133155 its reverse (551331301311), we get a palindrome (664434434466).
The spelling of 113103133155 in words is "one hundred thirteen billion, one hundred three million, one hundred thirty-three thousand, one hundred fifty-five".
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