Base | Representation |
---|---|
bin | 10000011101011011011… |
… | …011011111101001111011 |
3 | 11000010121000122102201012 |
4 | 100131123123133221323 |
5 | 122013003221124201 |
6 | 2223342551544135 |
7 | 144501653123666 |
oct | 20353333375173 |
9 | 4003530572635 |
10 | 1131110333051 |
11 | 3a6779327746 |
12 | 16327268b04b |
13 | 828811cb37a |
14 | 3ca631806dd |
15 | 1e651d025bb |
hex | 1075b6dfa7b |
1131110333051 has 2 divisors, whose sum is σ = 1131110333052. Its totient is φ = 1131110333050.
The previous prime is 1131110333039. The next prime is 1131110333063. The reversal of 1131110333051 is 1503330111311.
It is a balanced prime because it is at equal distance from previous prime (1131110333039) and next prime (1131110333063).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131110333051 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (1131110333651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565555166525 + 565555166526.
It is an arithmetic number, because the mean of its divisors is an integer number (565555166526).
Almost surely, 21131110333051 is an apocalyptic number.
1131110333051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131110333051 is an equidigital number, since it uses as much as digits as its factorization.
1131110333051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 405, while the sum is 23.
Adding to 1131110333051 its reverse (1503330111311), we get a palindrome (2634440444362).
The spelling of 1131110333051 in words is "one trillion, one hundred thirty-one billion, one hundred ten million, three hundred thirty-three thousand, fifty-one".
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