Base | Representation |
---|---|
bin | 10000011101011011100… |
… | …010100111011111010111 |
3 | 11000010121011011021220001 |
4 | 100131123202213133113 |
5 | 122013004210401101 |
6 | 2223343055552131 |
7 | 144502005031303 |
oct | 20353342473727 |
9 | 4003534137801 |
10 | 1131112200151 |
11 | 3a677a3924aa |
12 | 16327322b647 |
13 | 8288170316b |
14 | 3ca63508d03 |
15 | 1e652070901 |
hex | 1075b8a77d7 |
1131112200151 has 2 divisors, whose sum is σ = 1131112200152. Its totient is φ = 1131112200150.
The previous prime is 1131112200103. The next prime is 1131112200181. The reversal of 1131112200151 is 1510022111311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1131112200151 - 211 = 1131112198103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131112200181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565556100075 + 565556100076.
It is an arithmetic number, because the mean of its divisors is an integer number (565556100076).
Almost surely, 21131112200151 is an apocalyptic number.
1131112200151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131112200151 is an equidigital number, since it uses as much as digits as its factorization.
1131112200151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 19.
Adding to 1131112200151 its reverse (1510022111311), we get a palindrome (2641134311462).
The spelling of 1131112200151 in words is "one trillion, one hundred thirty-one billion, one hundred twelve million, two hundred thousand, one hundred fifty-one".
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