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1131112200103 is a prime number
BaseRepresentation
bin10000011101011011100…
…010100111011110100111
311000010121011011021211021
4100131123202213132213
5122013004210400403
62223343055552011
7144502005031204
oct20353342473647
94003534137737
101131112200103
113a677a392466
1216327322b607
1382881703132
143ca63508cab
151e6520708bd
hex1075b8a77a7

1131112200103 has 2 divisors, whose sum is σ = 1131112200104. Its totient is φ = 1131112200102.

The previous prime is 1131112200079. The next prime is 1131112200151. The reversal of 1131112200103 is 3010022111311.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1131112200103 is a prime.

It is a super-2 number, since 2×11311122001032 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131112200203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565556100051 + 565556100052.

It is an arithmetic number, because the mean of its divisors is an integer number (565556100052).

Almost surely, 21131112200103 is an apocalyptic number.

1131112200103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131112200103 is an equidigital number, since it uses as much as digits as its factorization.

1131112200103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 1131112200103 its reverse (3010022111311), we get a palindrome (4141134311414).

The spelling of 1131112200103 in words is "one trillion, one hundred thirty-one billion, one hundred twelve million, two hundred thousand, one hundred three".