1131114133 has 4 divisors (see below), whose sum is σ = 1131200928. Its totient is φ = 1131027340.

The previous prime is 1131114121. The next prime is 1131114157. The reversal of 1131114133 is 3314111311.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3314111311 = 7 ⋅473444473.

It is a cyclic number.

It is not a de Polignac number, because 1131114133 - 2²¹ = 1129016981 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1131114133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1131114113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19441 + ... + 51382.

It is an arithmetic number, because the mean of its divisors is an integer number (282800232).

Almost surely, 2^1131114133 is an apocalyptic number.

It is an amenable number.

1131114133 is a deficient number, since it is larger than the sum of its proper divisors (86795).

1131114133 is an equidigital number, since it uses as much as digits as its factorization.

1131114133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86794.

The product of its digits is 108, while the sum is 19.

The square root of 1131114133 is about 33632.0402741196. The cubic root of 1131114133 is about 1041.9226431939.

Adding to 1131114133 its reverse (3314111311), we get a palindrome (4445225444).

The spelling of 1131114133 in words is "one billion, one hundred thirty-one million, one hundred fourteen thousand, one hundred thirty-three".