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11311202213 = 98831144511
BaseRepresentation
bin10101000100011001…
…10011111110100101
31002012022000121102022
422202030303332211
5141131131432323
65110222152525
7550205426633
oct124214637645
932168017368
1011311202213
114884973703
122238122745
1310b354827c
1479435c353
154630624c8
hex2a2333fa5

11311202213 has 4 divisors (see below), whose sum is σ = 11312356608. Its totient is φ = 11310047820.

The previous prime is 11311202183. The next prime is 11311202233. The reversal of 11311202213 is 31220211311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11311202213 - 214 = 11311185829 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311202191 and 11311202200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311202233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 562373 + ... + 582138.

It is an arithmetic number, because the mean of its divisors is an integer number (2828089152).

Almost surely, 211311202213 is an apocalyptic number.

It is an amenable number.

11311202213 is a deficient number, since it is larger than the sum of its proper divisors (1154395).

11311202213 is an equidigital number, since it uses as much as digits as its factorization.

11311202213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1154394.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11311202213 its reverse (31220211311), we get a palindrome (42531413524).

The spelling of 11311202213 in words is "eleven billion, three hundred eleven million, two hundred two thousand, two hundred thirteen".

Divisors: 1 9883 1144511 11311202213