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11311202300112 = 2432111319314671997
BaseRepresentation
bin1010010010011001100000…
…1100011111000011010000
31111001100012010200111212200
42210212120030133003100
52440310320242100422
640020143344523200
72245131065116041
oct244463014370320
944040163614780
1011311202300112
1136710658a8080
12132822a920500
1364084605b4c0
142b16723a88c8
1514936c5682ac
hexa499831f0d0

11311202300112 has 960 divisors, whose sum is σ = 40516846755840. Its totient is φ = 2893095014400.

The previous prime is 11311202300107. The next prime is 11311202300113. The reversal of 11311202300112 is 21100320211311.

11311202300112 is a `hidden beast` number, since 1 + 131 + 120 + 2 + 300 + 112 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311202300113) by changing a digit.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 5664096298 + ... + 5664098294.

It is an arithmetic number, because the mean of its divisors is an integer number (42205048704).

Almost surely, 211311202300112 is an apocalyptic number.

11311202300112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11311202300112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20258423377920).

11311202300112 is an abundant number, since it is smaller than the sum of its proper divisors (29205644455728).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11311202300112 is a wasteful number, since it uses less digits than its factorization.

11311202300112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2552 (or 2543 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 11311202300112 its reverse (21100320211311), we get a palindrome (32411522511423).

The spelling of 11311202300112 in words is "eleven trillion, three hundred eleven billion, two hundred two million, three hundred thousand, one hundred twelve".