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113112130130 = 2511311213013
BaseRepresentation
bin110100101011000000…
…0100010001001010010
3101210221222102120022222
41221112000202021102
53323123201131010
6123544001301042
711113011146066
oct1512600421122
9353858376288
10113112130130
1143a7493758a
1219b09034782
13a8881b121c
145690657aa6
152e2043a355
hex1a56022252

113112130130 has 8 divisors (see below), whose sum is σ = 203601834252. Its totient is φ = 45244852048.

The previous prime is 113112130099. The next prime is 113112130177. The reversal of 113112130130 is 31031211311.

It can be written as a sum of positive squares in 2 ways, for example, as 112658908609 + 453221521 = 335647^2 + 21289^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 113112130099 and 113112130108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5655606497 + ... + 5655606516.

Almost surely, 2113112130130 is an apocalyptic number.

113112130130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113112130130 is a deficient number, since it is larger than the sum of its proper divisors (90489704122).

113112130130 is a wasteful number, since it uses less digits than its factorization.

113112130130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11311213020.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 113112130130 its reverse (31031211311), we get a palindrome (144143341441).

The spelling of 113112130130 in words is "one hundred thirteen billion, one hundred twelve million, one hundred thirty thousand, one hundred thirty".

Divisors: 1 2 5 10 11311213013 22622426026 56556065065 113112130130