11311243133 has 4 divisors (see below), whose sum is σ = 11338239360. Its totient is φ = 11284246908.

The previous prime is 11311243123. The next prime is 11311243159. The reversal of 11311243133 is 33134211311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11311243133 - 2¹⁴ = 11311226749 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311243099 and 11311243108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311243123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13497485 + ... + 13498322.

It is an arithmetic number, because the mean of its divisors is an integer number (2834559840).

Almost surely, 2^11311243133 is an apocalyptic number.

It is an amenable number.

11311243133 is a deficient number, since it is larger than the sum of its proper divisors (26996227).

11311243133 is an equidigital number, since it uses as much as digits as its factorization.

11311243133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26996226.

The product of its digits is 648, while the sum is 23.

Adding to 11311243133 its reverse (33134211311), we get a palindrome (44445454444).

The spelling of 11311243133 in words is "eleven billion, three hundred eleven million, two hundred forty-three thousand, one hundred thirty-three".