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141131134240013 is a prime number
BaseRepresentation
bin100000000101101110100111…
…000111111000010100001101
3200111201000010101212120111102
4200011232213013320110031
5121444243030331140023
61220054425323232445
741504250033503501
oct4005564707702415
9614630111776442
10141131134240013
1140a72417aa7605
12139b41ab378725
1360997bb85c5a8
1426bcad76d2301
15114b228462628
hex805ba71f850d

141131134240013 has 2 divisors, whose sum is σ = 141131134240014. Its totient is φ = 141131134240012.

The previous prime is 141131134239971. The next prime is 141131134240021. The reversal of 141131134240013 is 310042431131141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91039802424484 + 50091331815529 = 9541478^2 + 7077523^2 .

It is an emirp because it is prime and its reverse (310042431131141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141131134240013 - 216 = 141131134174477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141131134240093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565567120006 + 70565567120007.

It is an arithmetic number, because the mean of its divisors is an integer number (70565567120007).

Almost surely, 2141131134240013 is an apocalyptic number.

It is an amenable number.

141131134240013 is a deficient number, since it is larger than the sum of its proper divisors (1).

141131134240013 is an equidigital number, since it uses as much as digits as its factorization.

141131134240013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 141131134240013 its reverse (310042431131141), we get a palindrome (451173565371154).

The spelling of 141131134240013 in words is "one hundred forty-one trillion, one hundred thirty-one billion, one hundred thirty-four million, two hundred forty thousand, thirteen".