Base | Representation |
---|---|
bin | 1010010010011001111010… |
… | …0111101101101010000111 |
3 | 1111001100110122112101001212 |
4 | 2210212132213231222013 |
5 | 2440311030341214002 |
6 | 40020202155242035 |
7 | 2245133544321521 |
oct | 244463647555207 |
9 | 44040418471055 |
10 | 11311310101127 |
11 | 3671110737623 |
12 | 132825aa4931b |
13 | 6408624a399a |
14 | 2b168282aa11 |
15 | 149376c5e352 |
hex | a499e9eda87 |
11311310101127 has 2 divisors, whose sum is σ = 11311310101128. Its totient is φ = 11311310101126.
The previous prime is 11311310101087. The next prime is 11311310101141. The reversal of 11311310101127 is 72110101311311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11311310101127 - 232 = 11307015133831 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311310101627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655655050563 + 5655655050564.
It is an arithmetic number, because the mean of its divisors is an integer number (5655655050564).
Almost surely, 211311310101127 is an apocalyptic number.
11311310101127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311310101127 is an equidigital number, since it uses as much as digits as its factorization.
11311310101127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 23.
Adding to 11311310101127 its reverse (72110101311311), we get a palindrome (83421411412438).
The spelling of 11311310101127 in words is "eleven trillion, three hundred eleven billion, three hundred ten million, one hundred one thousand, one hundred twenty-seven".
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