11311311330133 has 4 divisors (see below), whose sum is σ = 11312062777548. Its totient is φ = 11310559882720.

The previous prime is 11311311330131. The next prime is 11311311330157. The reversal of 11311311330133 is 33103311311311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8910475741764 + 2400835588369 = 2985042^2 + 1549463^2 .

It is a cyclic number.

It is not a de Polignac number, because 11311311330133 - 2¹ = 11311311330131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11311311330098 and 11311311330107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311311330131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 375701128 + ... + 375731233.

It is an arithmetic number, because the mean of its divisors is an integer number (2828015694387).

Almost surely, 2^{11311311330133} is an apocalyptic number.

It is an amenable number.

11311311330133 is a deficient number, since it is larger than the sum of its proper divisors (751447415).

11311311330133 is an equidigital number, since it uses as much as digits as its factorization.

11311311330133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 751447414.

The product of its (nonzero) digits is 729, while the sum is 25.

Adding to 11311311330133 its reverse (33103311311311), we get a palindrome (44414622641444).

The spelling of 11311311330133 in words is "eleven trillion, three hundred eleven billion, three hundred eleven million, three hundred thirty thousand, one hundred thirty-three".