11311312000133 has 4 divisors (see below), whose sum is σ = 11470626253728. Its totient is φ = 11151997746540.

The previous prime is 11311312000117. The next prime is 11311312000169. The reversal of 11311312000133 is 33100021311311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11311312000133 - 2⁴ = 11311312000117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311312000033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79657126691 + ... + 79657126832.

It is an arithmetic number, because the mean of its divisors is an integer number (2867656563432).

Almost surely, 2^{11311312000133} is an apocalyptic number.

It is an amenable number.

11311312000133 is a deficient number, since it is larger than the sum of its proper divisors (159314253595).

11311312000133 is an equidigital number, since it uses as much as digits as its factorization.

11311312000133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159314253594.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 11311312000133 its reverse (33100021311311), we get a palindrome (44411333311444).

The spelling of 11311312000133 in words is "eleven trillion, three hundred eleven billion, three hundred twelve million, one hundred thirty-three", and thus it is an aban number.