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1131202002317 is a prime number
BaseRepresentation
bin10000011101100000111…
…001001011110110001101
311000010211102010201022012
4100131200321023312031
5122013200203033232
62223400024431005
7144504145241222
oct20354071136615
94003742121265
101131202002317
113a6816049172
12163299318465
13828971b603a
143ca71403949
151e659dad9b2
hex10760e4bd8d

1131202002317 has 2 divisors, whose sum is σ = 1131202002318. Its totient is φ = 1131202002316.

The previous prime is 1131202002277. The next prime is 1131202002331. The reversal of 1131202002317 is 7132002021311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 922731226921 + 208470775396 = 960589^2 + 456586^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131202002317 - 238 = 856324095373 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131202002292 and 1131202002301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131202002377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565601001158 + 565601001159.

It is an arithmetic number, because the mean of its divisors is an integer number (565601001159).

Almost surely, 21131202002317 is an apocalyptic number.

It is an amenable number.

1131202002317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131202002317 is an equidigital number, since it uses as much as digits as its factorization.

1131202002317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 1131202002317 its reverse (7132002021311), we get a palindrome (8263204023628).

The spelling of 1131202002317 in words is "one trillion, one hundred thirty-one billion, two hundred two million, two thousand, three hundred seventeen".