113121201002111 has 2 divisors, whose sum is σ = 113121201002112. Its totient is φ = 113121201002110.

The previous prime is 113121201001999. The next prime is 113121201002113. The reversal of 113121201002111 is 111200102121311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113121201002111 is a prime.

It is a super-3 number, since 3×113121201002111³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 113121201002113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 113121201002111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113121201002113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560600501055 + 56560600501056.

It is an arithmetic number, because the mean of its divisors is an integer number (56560600501056).

Almost surely, 2^{113121201002111} is an apocalyptic number.

113121201002111 is a deficient number, since it is larger than the sum of its proper divisors (1).

113121201002111 is an equidigital number, since it uses as much as digits as its factorization.

113121201002111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 113121201002111 its reverse (111200102121311), we get a palindrome (224321303123422).

The spelling of 113121201002111 in words is "one hundred thirteen trillion, one hundred twenty-one billion, two hundred one million, two thousand, one hundred eleven".