1131213111320 has 32 divisors (see below), whose sum is σ = 2545387107120. Its totient is φ = 452457225600.

The previous prime is 1131213111313. The next prime is 1131213111419. The reversal of 1131213111320 is 231113121311.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 1131213111292 and 1131213111301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 215402 + ... + 1519481.

Almost surely, 2^{1131213111320} is an apocalyptic number.

1131213111320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1131213111320 is an abundant number, since it is smaller than the sum of its proper divisors (1414173995800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1131213111320 is a wasteful number, since it uses less digits than its factorization.

1131213111320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1751195 (or 1751191 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1131213111320 its reverse (231113121311), we get a palindrome (1362326232631).

Subtracting from 1131213111320 its reverse (231113121311), we obtain a palindrome (900099990009).

The spelling of 1131213111320 in words is "one trillion, one hundred thirty-one billion, two hundred thirteen million, one hundred eleven thousand, three hundred twenty".