Base | Representation |
---|---|
bin | 10000011101100001100… |
… | …100010111000001101101 |
3 | 11000010212012102201122210 |
4 | 100131201210113001231 |
5 | 122013211102222201 |
6 | 2223401111201033 |
7 | 144504343400241 |
oct | 20354144270155 |
9 | 4003765381583 |
10 | 1131213320301 |
11 | 3a6821479579 |
12 | 1632a1076179 |
13 | 8289964977c |
14 | 3ca72b0c421 |
15 | 1e65ad971d6 |
hex | 1076191706d |
1131213320301 has 4 divisors (see below), whose sum is σ = 1508284427072. Its totient is φ = 754142213532.
The previous prime is 1131213320291. The next prime is 1131213320329. The reversal of 1131213320301 is 1030233121311.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1131213320301 - 210 = 1131213319277 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1131213320381) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188535553381 + ... + 188535553386.
It is an arithmetic number, because the mean of its divisors is an integer number (377071106768).
Almost surely, 21131213320301 is an apocalyptic number.
It is an amenable number.
1131213320301 is a deficient number, since it is larger than the sum of its proper divisors (377071106771).
1131213320301 is an equidigital number, since it uses as much as digits as its factorization.
1131213320301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 377071106770.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 1131213320301 its reverse (1030233121311), we get a palindrome (2161446441612).
The spelling of 1131213320301 in words is "one trillion, one hundred thirty-one billion, two hundred thirteen million, three hundred twenty thousand, three hundred one".
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