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113122020211200 = 293252711133726513
BaseRepresentation
bin11001101110001001000101…
…110101001011101000000000
3112211112100201002101000211200
4121232021011311023220000
5104311342344133224300
61040331312203541200
732553540054456630
oct3156110565135000
9484470632330750
10113122020211200
1133053863362620
121082b97b82a800
134b1748c6bb360
141dd11c65ba6c0
15d1286b463200
hex66e245d4ba00

113122020211200 has 2880 divisors, whose sum is σ = 558262938385152. Its totient is φ = 21110508748800.

The previous prime is 113122020211129. The next prime is 113122020211201. The reversal of 113122020211200 is 2112020221311.

113122020211200 is a `hidden beast` number, since 1 + 1 + 31 + 220 + 2 + 0 + 211 + 200 = 666.

It is a tau number, because it is divible by the number of its divisors (2880).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (113122020211201) by changing a digit.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 4266649144 + ... + 4266675656.

Almost surely, 2113122020211200 is an apocalyptic number.

113122020211200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113122020211200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (279131469192576).

113122020211200 is an abundant number, since it is smaller than the sum of its proper divisors (445140918173952).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113122020211200 is a wasteful number, since it uses less digits than its factorization.

113122020211200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26615 (or 26591 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 113122020211200 its reverse (2112020221311), we get a palindrome (115234040432511).

The spelling of 113122020211200 in words is "one hundred thirteen trillion, one hundred twenty-two billion, twenty million, two hundred eleven thousand, two hundred".