Base | Representation |
---|---|
bin | 1010010010011101100110… |
… | …1100011101011101010000 |
3 | 1111001110000201110110211011 |
4 | 2210213121230131131100 |
5 | 2440320043101414412 |
6 | 40020444402100304 |
7 | 2245200240454303 |
oct | 244473154353520 |
9 | 44043021413734 |
10 | 11312301201232 |
11 | 367157a131819 |
12 | 132849694a694 |
13 | 64098c915c55 |
14 | 2b17382dcb3a |
15 | 1493d3c837a7 |
hex | a49d9b1d750 |
11312301201232 has 10 divisors (see below), whose sum is σ = 21917583577418. Its totient is φ = 5656150600608.
The previous prime is 11312301201209. The next prime is 11312301201251. The reversal of 11312301201232 is 23210210321311.
11312301201232 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 9257390419216 + 2054910782016 = 3042596^2 + 1433496^2 .
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 353509412523 + ... + 353509412554.
Almost surely, 211312301201232 is an apocalyptic number.
It is an amenable number.
11312301201232 is a deficient number, since it is larger than the sum of its proper divisors (10605282376186).
11312301201232 is an equidigital number, since it uses as much as digits as its factorization.
11312301201232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 707018825085 (or 707018825079 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 11312301201232 its reverse (23210210321311), we get a palindrome (34522511522543).
The spelling of 11312301201232 in words is "eleven trillion, three hundred twelve billion, three hundred one million, two hundred one thousand, two hundred thirty-two".
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