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11312400131 = 67168841793
BaseRepresentation
bin10101000100100010…
…11000011100000011
31002012101021110122122
422202101120130003
5141131433301011
65110303554455
7550221546254
oct124221303403
932171243578
1011312400131
11488561171a
1222385bba2b
1310b38775b6
14794590b2b
154631ec3db
hex2a2458703

11312400131 has 4 divisors (see below), whose sum is σ = 11481241992. Its totient is φ = 11143558272.

The previous prime is 11312400119. The next prime is 11312400157. The reversal of 11312400131 is 13100421311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11312400131 - 26 = 11312400067 is a prime.

It is a super-2 number, since 2×113124001312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11312400731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84420830 + ... + 84420963.

It is an arithmetic number, because the mean of its divisors is an integer number (2870310498).

Almost surely, 211312400131 is an apocalyptic number.

11312400131 is a deficient number, since it is larger than the sum of its proper divisors (168841861).

11312400131 is an equidigital number, since it uses as much as digits as its factorization.

11312400131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 168841860.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11312400131 its reverse (13100421311), we get a palindrome (24412821442).

The spelling of 11312400131 in words is "eleven billion, three hundred twelve million, four hundred thousand, one hundred thirty-one".

Divisors: 1 67 168841793 11312400131