11312410013 has 4 divisors (see below), whose sum is σ = 11336843328. Its totient is φ = 11287976700.

The previous prime is 11312410009. The next prime is 11312410027. The reversal of 11312410013 is 31001421311.

11312410013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11312410013 - 2² = 11312410009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11312409973 and 11312410000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312410093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12215963 + ... + 12216888.

It is an arithmetic number, because the mean of its divisors is an integer number (2834210832).

Almost surely, 2^11312410013 is an apocalyptic number.

It is an amenable number.

11312410013 is a deficient number, since it is larger than the sum of its proper divisors (24433315).

11312410013 is an equidigital number, since it uses as much as digits as its factorization.

11312410013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24433314.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11312410013 its reverse (31001421311), we get a palindrome (42313831324).

The spelling of 11312410013 in words is "eleven billion, three hundred twelve million, four hundred ten thousand, thirteen".