11312535253 has 2 divisors, whose sum is σ = 11312535254. Its totient is φ = 11312535252.

The previous prime is 11312535251. The next prime is 11312535263. The reversal of 11312535253 is 35253521311.

11312535253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8652348324 + 2660186929 = 93018^2 + 51577^2 .

It is an emirp because it is prime and its reverse (35253521311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11312535253 - 2¹ = 11312535251 is a prime.

Together with 11312535251, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312535251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656267626 + 5656267627.

It is an arithmetic number, because the mean of its divisors is an integer number (5656267627).

Almost surely, 2^11312535253 is an apocalyptic number.

It is an amenable number.

11312535253 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312535253 is an equidigital number, since it uses as much as digits as its factorization.

11312535253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13500, while the sum is 31.

The spelling of 11312535253 in words is "eleven billion, three hundred twelve million, five hundred thirty-five thousand, two hundred fifty-three".