Base | Representation |
---|---|
bin | 10101000100100111… |
… | …01101010101010101 |
3 | 1002012102102110020120 |
4 | 22202103231111111 |
5 | 141132112310010 |
6 | 5110325022153 |
7 | 550226666313 |
oct | 124223552525 |
9 | 32172373216 |
10 | 11313010005 |
11 | 4885998950 |
12 | 2238854959 |
13 | 10b3a2c07b |
14 | 7946ad0b3 |
15 | 4632bce70 |
hex | 2a24ed555 |
11313010005 has 32 divisors (see below), whose sum is σ = 19897118208. Its totient is φ = 5443214400.
The previous prime is 11313009991. The next prime is 11313010057. The reversal of 11313010005 is 50001031311.
11313010005 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11313010005 - 28 = 11313009749 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 240079 + ... + 283308.
It is an arithmetic number, because the mean of its divisors is an integer number (621784944).
Almost surely, 211313010005 is an apocalyptic number.
11313010005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11313010005 is a deficient number, since it is larger than the sum of its proper divisors (8584108203).
11313010005 is a wasteful number, since it uses less digits than its factorization.
11313010005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 523537.
The product of its (nonzero) digits is 45, while the sum is 15.
Adding to 11313010005 its reverse (50001031311), we get a palindrome (61314041316).
The spelling of 11313010005 in words is "eleven billion, three hundred thirteen million, ten thousand, five".
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