Base | Representation |
---|---|
bin | 10101000100100111… |
… | …10000000101100011 |
3 | 1002012102110000201021 |
4 | 22202103300011203 |
5 | 141132113140113 |
6 | 5110325150311 |
7 | 550230044224 |
oct | 124223600543 |
9 | 32172400637 |
10 | 11313021283 |
11 | 48859a6373 |
12 | 223885b397 |
13 | 10b3a34245 |
14 | 7946b324b |
15 | 4632c148d |
hex | 2a24f0163 |
11313021283 has 2 divisors, whose sum is σ = 11313021284. Its totient is φ = 11313021282.
The previous prime is 11313021281. The next prime is 11313021341. The reversal of 11313021283 is 38212031311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11313021283 - 21 = 11313021281 is a prime.
It is a super-2 number, since 2×113130212832 (a number of 21 digits) contains 22 as substring.
Together with 11313021281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11313021281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656510641 + 5656510642.
It is an arithmetic number, because the mean of its divisors is an integer number (5656510642).
Almost surely, 211313021283 is an apocalyptic number.
11313021283 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313021283 is an equidigital number, since it uses as much as digits as its factorization.
11313021283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 11313021283 its reverse (38212031311), we get a palindrome (49525052594).
The spelling of 11313021283 in words is "eleven billion, three hundred thirteen million, twenty-one thousand, two hundred eighty-three".
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