Base | Representation |
---|---|
bin | 1010010010100000100111… |
… | …1110011001101111111111 |
3 | 1111001112010011122020100012 |
4 | 2210220021332121233333 |
5 | 2440323222432223012 |
6 | 40021101015253435 |
7 | 2245226304440654 |
oct | 244501176315777 |
9 | 44045104566305 |
10 | 11313111211007 |
11 | 367195538a091 |
12 | 132868207a27b |
13 | 640a8b691c88 |
14 | 2b17b3b11c2b |
15 | 14942ee36622 |
hex | a4a09f99bff |
11313111211007 has 2 divisors, whose sum is σ = 11313111211008. Its totient is φ = 11313111211006.
The previous prime is 11313111210967. The next prime is 11313111211043. The reversal of 11313111211007 is 70011211131311.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (70011211131311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11313111211007 - 26 = 11313111210943 is a prime.
It is a super-2 number, since 2×113131112110072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11313111211307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656555605503 + 5656555605504.
It is an arithmetic number, because the mean of its divisors is an integer number (5656555605504).
Almost surely, 211313111211007 is an apocalyptic number.
11313111211007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11313111211007 is an equidigital number, since it uses as much as digits as its factorization.
11313111211007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126, while the sum is 23.
Adding to 11313111211007 its reverse (70011211131311), we get a palindrome (81324322342318).
The spelling of 11313111211007 in words is "eleven trillion, three hundred thirteen billion, one hundred eleven million, two hundred eleven thousand, seven".
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