Base | Representation |
---|---|
bin | 1010010010100000101010… |
… | …0100111000111010011000 |
3 | 1111001112010212121211000001 |
4 | 2210220022210320322120 |
5 | 2440323233023100440 |
6 | 40021102015422344 |
7 | 2245226456261203 |
oct | 244501244707230 |
9 | 44045125554001 |
10 | 11313121300120 |
11 | 36719600501a2 |
12 | 13286855249b4 |
13 | 640a907b5273 |
14 | 2b17b51ba93a |
15 | 149430c7ab9a |
hex | a4a0a938e98 |
11313121300120 has 64 divisors (see below), whose sum is σ = 25963231595040. Its totient is φ = 4435335705600.
The previous prime is 11313121300051. The next prime is 11313121300141. The reversal of 11313121300120 is 2100312131311.
It is a super-2 number, since 2×113131213001202 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7501221 + ... + 8882260.
Almost surely, 211313121300120 is an apocalyptic number.
11313121300120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11313121300120 is an abundant number, since it is smaller than the sum of its proper divisors (14650110294920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313121300120 is a wasteful number, since it uses less digits than its factorization.
11313121300120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16383836 (or 16383832 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 11313121300120 its reverse (2100312131311), we get a palindrome (13413433431431).
The spelling of 11313121300120 in words is "eleven trillion, three hundred thirteen billion, one hundred twenty-one million, three hundred thousand, one hundred twenty".
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