Base | Representation |
---|---|
bin | 1010010010100000101110… |
… | …1100001111000010111011 |
3 | 1111001112012011211000112102 |
4 | 2210220023230033002323 |
5 | 2440323302320044003 |
6 | 40021103524334015 |
7 | 2245230104245436 |
oct | 244501354170273 |
9 | 44045164730472 |
10 | 11313140003003 |
11 | 367196a664a23 |
12 | 132868b84430b |
13 | 640a94633167 |
14 | 2b17b788881d |
15 | 149432722588 |
hex | a4a0bb0f0bb |
11313140003003 has 4 divisors (see below), whose sum is σ = 11313234517800. Its totient is φ = 11313045488208.
The previous prime is 11313140002987. The next prime is 11313140003021. The reversal of 11313140003003 is 30030004131311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11313140003003 - 24 = 11313140002987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11313140003023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47077625 + ... + 47317322.
It is an arithmetic number, because the mean of its divisors is an integer number (2828308629450).
Almost surely, 211313140003003 is an apocalyptic number.
11313140003003 is a deficient number, since it is larger than the sum of its proper divisors (94514797).
11313140003003 is an equidigital number, since it uses as much as digits as its factorization.
11313140003003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 94514796.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 11313140003003 its reverse (30030004131311), we get a palindrome (41343144134314).
The spelling of 11313140003003 in words is "eleven trillion, three hundred thirteen billion, one hundred forty million, three thousand, three".
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