11313140003023 has 2 divisors, whose sum is σ = 11313140003024. Its totient is φ = 11313140003022.

The previous prime is 11313140003021. The next prime is 11313140003201. The reversal of 11313140003023 is 32030004131311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11313140003023 - 2¹ = 11313140003021 is a prime.

Together with 11313140003021, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11313140002985 and 11313140003003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11313140003021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656570001511 + 5656570001512.

It is an arithmetic number, because the mean of its divisors is an integer number (5656570001512).

Almost surely, 2^{11313140003023} is an apocalyptic number.

11313140003023 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313140003023 is an equidigital number, since it uses as much as digits as its factorization.

11313140003023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 11313140003023 its reverse (32030004131311), we get a palindrome (43343144134334).

The spelling of 11313140003023 in words is "eleven trillion, three hundred thirteen billion, one hundred forty million, three thousand, twenty-three".